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64x^2+24x+2=0
a = 64; b = 24; c = +2;
Δ = b2-4ac
Δ = 242-4·64·2
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8}{2*64}=\frac{-32}{128} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8}{2*64}=\frac{-16}{128} =-1/8 $
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